A computer algebra system written in pure Python http://sympy.org/ . To get started to with contributing https://github.com/sympy/sympy/wiki/Introduction-to-contributing
smichr on master
EmptySet/Complexes/nan usage fix #22338 Merge pull request #22370 from … (compare)
smichr on master
improve handling when Range.inf… check discrete when processing Merge pull request #22363 from … (compare)
I saw that in the google groups people had mentioned what idea they want to do for gsoc and were having discussions on the same. I too posted my idea yet there was no response from anyone, are there any other prerequisites before discussing project idea on the google group?
No, there are no prerequisites to presenting or discussing any idea for GSoC, or otherwise. You are free to start any discussion on an idea you might feel useful for SymPy.
As for your post, the mentors for your idea might have been preoccupied with some work, so they might not have replied. What was your idea btw?
Hey everyone, I am Sarthak Srivastava. I would like to contribute in SymPY's mathematics's projects. Although, I am pursuing cse from MSIT but maths has always intrigued me. So, kindly let me know what to do.
Hi Sarthak,
You can check out https://github.com/sympy/sympy/wiki/Introduction-to-contributing and https://github.com/sympy/sympy/wiki/Development-workflow to get started with development. You can also check out https://github.com/sympy/sympy/blob/master/README.rst for general installation and usage instructions.
def test_solver(eq, hint)
in test_ode.py but it throws an exception for missing argument as sympy runs test_file by calling every function.
@jksuom Oh,... eh,... terribly confused now,... you are saying I can use a SymPy Symbol as as a key in a dictionary?
ParameterName = "I" # But then dynamiccaly
_self.values[Symbol(ParameterName)] = 42
I think it is there https://github.com/sympy/sympy_doc
That's auto-generated. You should not manually make changes to that repo.
cancel
does with rational functions)
minpoly
. minpoly((sqrt(x)+1)/(sqrt(x)*(x+sqrt(x)), y)
gives x*y - 1
meaning that the expression equals 1/x